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| − | <ggb_applet width="679" height="617" version="4.2" ggbBase64=" | + | __NOTOC__ |
| + | Fülle die Wertetabelle mit Hilfe eines Taschenrechners vollständig aus. | ||
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| + | {| border="1" cellspacing="0" valign="top" | ||
| + | | width="3%" | x | ||
| + | | width="2%" | <center>- 1,5</center> | ||
| + | | width="2%" | <center>- 1</center> | ||
| + | | width="2%" | <center>- 0,5</center> | ||
| + | | width="2%" | <center>0</center> | ||
| + | | width="2%" | <center>0,5</center> | ||
| + | | width="2%" | <center>1</center> | ||
| + | | width="2%" | <center>1,5</center> | ||
| + | |-valign="top" | ||
| + | | f(x) = x<sup>4</sup> - 3x² + 1 | ||
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| + | |g(x) = 2 f(x) | ||
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| + | |-valign="top" | ||
| + | |h(x) = 1/2 f(x) | ||
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| + | |} | ||
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| + | Wie ändern sich die Funktionswerte von f (x) im Vergleich zu g(x) = 2 f (x), bzw. zu h(x) = 1/2 f (x)? | ||
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Version vom 25. Mai 2013, 11:33 Uhr
Fülle die Wertetabelle mit Hilfe eines Taschenrechners vollständig aus.
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| f(x) = x4 - 3x² + 1 | |||||||
| g(x) = 2 f(x) | |||||||
| h(x) = 1/2 f(x) |
Wie ändern sich die Funktionswerte von f (x) im Vergleich zu g(x) = 2 f (x), bzw. zu h(x) = 1/2 f (x)?
